Chemical diagram showing the reaction of Compeund 3 and Compound 4 to form a dipeptide with the release of H2O.

draw a text-based skeletal diagram of the dipeptide formed when Compound 3 and Compound 4 react via a condensation reaction between the –NH₂ of Compound 3 and the –COOH of Compound 4. 🧪 Reaction Summary: Amine (NH₂) of Compound 3 reacts with Carboxylic acid (COOH) of Compound 4 Forms a peptide bond: –CO–NH– Water is removed (H₂O) 🔸 Text-based Skeletal Structure of the Product: markdown Copy Edit CH3 | CH3–CH–CH2–NH–CO–CH–CH2–CH3 | CH3 💬 Explanation: The left side is based on Compound 3: Central carbon has two branches: one methyl (CH₃), one ethyl (CH₂CH₃). The NH₂ becomes –NH– in the peptide bond. The right side is based on Compound 4: Central carbon bonded to CH₂CH₃, and a CH₃ group. The COOH group becomes –CO– in the peptide bond. The peptide bond is shown as: –NH–CO– See more